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3 years ago

What would the equation be??

Mathematics

1 answer:

makkiz [27]3 years ago

5 0

Answer:

y = 4x + 8

Step-by-step explanation:

Firstly, choose 2 points ( I chose [2,11] and [4,19] ) use y2-y1/x2-x1 to find your slope of 4, next use one of the points to find your y-intercept, plug the two coordinates into your equation to get 11 = 4 (2) + b , after simplifying, your answer is y = 4x + 8

Brainliest would be appreciated. :-)

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2 years ago

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3 years ago

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3 years ago

Find the radius of the circle. The center of the circle is (2, -3) and a point that lies on the circle is (-1, -2).

kirill [66]

Answer:

$\displaystyle r = \sqrt{10}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Geometry

Definition of a radius - the center of a circle to any point to the circumference

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Center (2, -3) → x₁ = 2, y₁ = -3

Circumference point (-1, -2) → x₂ = -1, y₂ = -2

In this case, the distance d from the center to the circumference point would be the radius r of the circle.

Step 2: Find Radius r

[Distance Formula] Define equation [Radius]: $\displaystyle r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Substitute in points [Radius]: $\displaystyle r = \sqrt{(-1-2)^2+(-2--3)^2}$
[Radius] [√Radical] (Parenthesis) Simplify: $\displaystyle r = \sqrt{(-1-2)^2+(-2+3)^2}$
[Radius] [√Radical] (Parenthesis) Subtract/Add: $\displaystyle r = \sqrt{(-3)^2+(1)^2}$
[Radius] [√Radical] Evaluate exponents: $\displaystyle r = \sqrt{9+1}$
[Radius] [√Radical] Add: $\displaystyle r = \sqrt{10}$

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3 years ago

What would the equation be??​

What would the equation be??