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Rudiy27
3 years ago
10

Order of operations : simplify completely (6-2X2)X3

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

6 is the answer.

Step-by-step explanation:

Using PEMDAS, let's solve.

  • (6 - 2 x 2) x 3
  • (6 - 4) x 3
  • 2 x 3
  • 6

Therefore, 6 is the answer.

Hoped this helped.

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Mila [183]

Answer:

m\angle H = 44.4\°.

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7    ....Side opposite to angle H

GH = 10  .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

sin \ H = \frac{Oppsite\  side\  to\  \angle H}{Hypotenuse}

Substituting the values we get;

sin\ H = \frac{7}{10} = 0.7

Now taking sin^{-1} we get;

\angle H = sin^{-1}\ 0.7 = 44.427

rounding to nearest tenth we get.

m\angle H = 44.4\°.

Hence m\angle H = 44.4\°.

6 0
3 years ago
A. Plot the data for the functions f(x) and g(x) on a grid and connect the points.
labwork [276]

Answer:

  a) see the plots below

  b) f(x) is exponential; g(x) is linear (see below for explanation)

  c) the function values are never equal

Step-by-step explanation:

a) a graph of the two function values is attached

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b) Adjacent values of f(x) have a common ratio of 3, so f(x) is exponential (with a base of 3). Adjacent values of g(x) have a common difference of 2, so g(x) is linear (with a slope of 2).

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c) At x ≥ 1, the slope of f(x) is greater than the slope of g(x), and the value of f(x) is greater than the value of g(x), so the curves can never cross for x > 1. Similarly, for x ≤ 0, the slope of f(x) is less than the slope of g(x). Once again, f(0) is greater than g(0), so the curves can never cross.

In the region between x=0 and x=1, f(x) remains greater than g(x). The smallest difference is about 0.73, near x = 0.545, where the slopes of the two functions are equal.

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3 years ago
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3 0
3 years ago
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zimovet [89]

Answer is given below

Step-by-step explanation:

given data

average length of all 1015 fishes = 98.06 mm

randomly selects 50 fishes average length = 101.04 mm

solution

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