Answer:
a.) 5(3t+2)+ 7(2t+5)
b.) 15t+10+14th+35
c.) $132
Step-by-step explanation:
a.) 5(3t+2)+ 7(2t+5)
b.) 15t+10+14th+35
Simplify to :
29t+45
c.) Substitute
29(3) +45
87+45=132
$132
Answer:
<h2>11.1111111111 or 1.1 <-(rounded)</h2>
Step-by-step explanation:
4+6+7+7+11+12+15+18+20= 100
divide by the number of values we have. we have 9 values
100/9=11.1111111111
I hope this helped
Answer:
The solution is ![\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2A%20tan%5E%7B-1%7D%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B5%7D%20%5D%20%2B%20%20C)
Step-by-step explanation:
From the question
The function given is 
The indefinite integral is mathematically represented as

Now let 
=> 
=> 
So

![= \frac{1}{2} \frac{tan^{-1} [\frac{u}{5} ]}{5} + C](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Btan%5E%7B-1%7D%20%5B%5Cfrac%7Bu%7D%7B5%7D%20%5D%7D%7B5%7D%20%20%2B%20%20C)
Now substituting for u
![\frac{1}{10} * tan^{-1}[\frac{e^{2x}}{5} ] + C](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B10%7D%20%2A%20tan%5E%7B-1%7D%5B%5Cfrac%7Be%5E%7B2x%7D%7D%7B5%7D%20%5D%20%2B%20%20C)