Years for one serious accident is 10 year
<u>Given:</u>
Probability of having a serious accident = 10% every year
P(serious accident) = 0.1
Number of years = n
<u>Computation:</u>
Years for one serious accident = 1 / Probability of having a serious accident
Years for one serious accident = 1 / P(serious accident)
Years for one serious accident = 1 / 0.1
Years for one serious accident = 10 year
Learn more:
brainly.com/question/23044118?referrer=searchResults
Answer:
x = 2![\sqrt{66}](https://tex.z-dn.net/?f=%5Csqrt%7B66%7D)
Step-by-step explanation:
x = ![\sqrt{2^2+8^2+14^2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%5E2%2B8%5E2%2B14%5E2%7D)
= ![\sqrt{4+64+196}](https://tex.z-dn.net/?f=%5Csqrt%7B4%2B64%2B196%7D)
= ![\sqrt{264}](https://tex.z-dn.net/?f=%5Csqrt%7B264%7D)
= 2![\sqrt{66}](https://tex.z-dn.net/?f=%5Csqrt%7B66%7D)
Equation would be: Y = 25 + 5x
Where, x = number of weeks
So, when x = 1, Y = 25 + 5(1) = 25+5 = 30
When x = 2, Y = 25 + 5(2) = 25 + 10 = 35
x = 3, Y = 25 + 5(3) = 25 + 15 = 40
So, Mark the coordinates: (0, 25), (1, 30), (2, 35), (3, 40), (4, 45), (5, 50)...
And draw a line...Graph is done!
Hope this helps!
Answer:
u^2 +7u -8=0 where u = 3x+2
Step-by-step explanation:
(3x+2)^2 + 7(3x+2) - 8=0
Let 3x+2 = u
u^2 +7u -8=0