Answer:
Option D
Step-by-step explanation:
A third of a shipment of books is 28 pounds. <u>Assuming that 'f' will be the total weight of the entire shipment,</u> we would divide 'f' by 3 to get 28.
The answer should be D.
Answer: 30 pounds of coffee beans worth $10.50 per pound was used.
20 pounds of coffee beans worth $13.00 per pound was used.
Step-by-step explanation:
Let x represent the number of coffee beans worth $10.50 per pound that should be mixed.
Let y represent the number of coffee beans worth $13.00 per pound that should be mixed.
50 pounds of beans worth $11.50 per pound is to be made. The total cost of the mixture would be
50 × 11.5 = 575
This means that
10.5x + 13y = 575 - - - - - - - 1
The total number of pounds of each type of coffee used is 50. This means that
x + y = 50
Substituting x = 50 - y into equation 1, it becomes.
10.5(50 - y) + 13y = 575
525 - 10.5y + 13y = 575
- 10.5y + 13y = 575 - 525
2.5y = 50
y = 50/2.5 = 20
x = 50 - 20= 30
3/5 is your answer. Hope this helps. There’s a picture attached with the work.
Answer:
Sample mean =119.42
Median = 92
25% trimmed mean = 102.42
10% trimmed mean = 95.69
Step-by-step explanation:
Data in increasing order :
12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513
Total no. of observations = 50
Sample mean =
=
= 119.42
Median: Since we have even number of observation
Median =
=
= 92
10% Trimmed Mean: We remove 5 values from each side
Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249
Trimmed mean =
=
= 102.42
25% Trimmed Mean: We remove 12 values from each side.
Trimmed set = 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141
Trimmed mean =
=
= 95.69