All categories

3 years ago

Look at the figure below:

Mathematics

1 answer:

labwork [276]3 years ago

7 0

The answer to this question is 10 units

You might be interested in

The area of a cross section through the center of a sphere is 46 square inches. Find the surface area of the sphere.

gavmur [86]

Answer:

184 in.^2

Step-by-step explanation:

The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.

area of circle

$A_{circle} = \pi r^2$

$\pi r^2 = 46$

$r^2 = \dfrac{46}{\pi}$

$r = \sqrt{\dfrac{46}{\pi}}$

$r = 3.83 ~in.$

surface area of sphere

$SA = 4 \pi r^2$

$SA = 4 \times \pi \times (3.83)^2$

$SA = 184~in.^2$

7 0

3 years ago

Gena wants to estimate the quotient of –21.87 divided by 4.79. Which expression shows the best expression to estimate the quotie

allochka39001 [22]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are two red jars of marbles and one blue jar of marbles jars of a certain color have the same number of marbles in them. T

satela [25.4K]

We can set up an equation to solve this problem. I am setting the number of marbles in a red jar to R.

R + R + R - 16 = 41

We solve this by adding 16 to both sides and combining all of the R terms.. This gives us:

3R = 57

We can finish this problem by dividing both sides by 3.

R = 19. So, there are 19 marbles in a red jar.

We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles. I am setting the amount of marbles in a blue jar to B.

41 - 19*2 = B

B = 3

So, there are 3 marbles in a blue jar and 19 marbles in a red jar.

7 0

3 years ago

What is the solution set for 2x+5y>-1 and 4x-3<-3?

bekas [8.4K]

PROBLEM ONE

•

Solving for x in 2x + 5y > -1.

•

Step 1 ) Subtract 5y from both sides.

2x + 5y > -1

2x + 5y - 5y > -1 - 5y

2x > -1 - 5y

Step 2 ) Divide both sides by 2.

2x > -1 - 5y

$\displaystyle\frac{2x}{2} > \displaystyle\frac{-1 - 5y}{2}$

$\displaystyle\ x > \frac{-1 - 5y}{2}$

So, the solution for x in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 - 5y}{2}$

•

Solving for y in 2x + 5y > -1.

•

Step 1 ) Subtract 2x from both sides.

2x + 5y > -1

2x - 2x + 5y > -1 - 2x

5y > -1 - 1x

Step 2 ) Divide both sides by 5.

5y > -1 - 1x

$\displaystyle\frac{5x}{5} > \frac{-1 -1x}{5}$

$\displaystyle\ x > \frac{-1 -1x}{5}$

So, the solution for y in 2x + 5y > -1 is...

$\displaystyle\ x > \frac{-1 -1x}{5}$

•

PROBLEM TWO

•

Solving for x in 4x - 3 < -3.

•

Step 1 ) Subtract 3 from both sides.

4x - 3 < -3

4x -3 - 3 < -3 - 3

4x < 0

Step 2 ) Divide both sides by x.

4x < 0

$\displaystyle\frac{4x}{4}$

x < 0

So, the solution for x in 4x - 3 < -3 is...

x < 0

•

- <em>Marlon Nunez</em>

7 0

3 years ago

Select the ratios whose simplest form is 8/7

kap26 [50]

48:42
16:14
56:49
I hope this helps.

8 0

3 years ago