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sasho [114]
2 years ago
15

The temperature of a liquid in an experiment is at 0 degrees Celsius at 9 am. The experiment calls for the temperature to drop 1

.25 degrees Celsius every hour. What will the temperature be at noon?
Mathematics
1 answer:
RSB [31]2 years ago
8 0

Answer:

don't know don't know don't know don't know don't know don't know don't know

Step-by-step explanation:

don't know don't know don't know don't know don't know don't know don't know don't know

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What does x and oe equal?
dimaraw [331]

Answer:

œ=50

Step-by-step explanation:

Solve the equation: 120+œ+60+15+20 = 130+35+2œ

Simplifies as follows: œ+215 = 2œ+165

œ = 215 - 165 = 50

6 0
3 years ago
The multiplicative inverse of - 5 and 10v - 5
Digiron [165]
The answer is 1/5 hope this helps
3 0
3 years ago
Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
HELP ITS SOO HARD also can you please explain how to get the answer to where a dummy can understand cuz well I’m a dummy
Ksenya-84 [330]

Answer:

244.92 square inches

Step-by-step explanation:

You just have to fill in the formula with the information they gave you.

They gave you the diameter for base circle so you divide that number in half to get the radius which is what you need for the formula represent as "r".

r=3

h=10

and you know pi is 3.14

so just plug in the numbers.

SA=2x3.14x3^2+2x3.14x3x10

SA=6.28x9+6.28x30

SA=56.52+188.4

SA=244.92

7 0
3 years ago
Find the value of x that will make a||b help ?
nydimaria [60]

Answer:

x=30

Step-by-step explanation:

Find the value of x that will make A and B parallel

For A & B to be parallel, the interior angles must be supplementary, i.e.

4x+2x = 180

6x=180

x=30

When x=30, the interior angles are 120 and 60 which are supplementary.

4 0
3 years ago
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