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Marina86 [1]
3 years ago
11

Solve the equation

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0
X/-14 = 13
x=13+14
x=27
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!
Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20   (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8          (2)

He wants to spend no more than 15 hours doing cardio exercises, this is:

y ≤ 15     (3)

The graph of the equations was plotted using geogebra graphing and attached.

Find out more at: brainly.com/question/17178834

3 0
3 years ago
Javier had $305 in his bank account. His bank charges a fee of $7.50 each month that a balance is below $500. If he makes no oth
Likurg_2 [28]
7.50*3 = 22.50
305 - 22.50 = 282.50
8 0
3 years ago
Read 2 more answers
Which solve the problem correctly <br> PLEASE HELP:p<br> 30 POINTS?!!
Drupady [299]

Answer: :( incorrect :( :( :( :(  = (

                                           

Step-by-step explanation:

3 0
2 years ago
12. In the toy factory where you work, you inspect each toy for
Andrej [43]
67:938
But when you reduce this ratio your final answer is 1:14
3 0
3 years ago
9. Simran had some ₹2 and ₹ 5 coins.She exchanged them for ₹ 10 coins. If the number of ₹ 5 coins is one less than the number of
sertanlavr [38]

Answer:

Step-by-step explanation:

Let x be the number of 2 coins and y be the number of 5 coins. Let z be the number of 10 coins she exchanged. Then, we have the first equation

2x+5y = 10z

Since she has one 5 coin less than 2 coins, then y=x-1. So we get the equation

2x+5(x-1) = 10z

which is equivalent to

7x-5 = 10z

If we add 5 on both sides and factor out on the right by 5 we get

7x = 5(2z+1)

We can solve for x and get

x = \frac{5(2z+1)}{7}

Since x represents the number of 2 coins, we must have that x is an integer. That is, we cannot have, for example 1.5 2 coins. Since 7 doesn't divide 5, we must have that 7 divides 2z+1. That is, the value of z is such that the number 2z+1 is multiple of 7. That is 2z+1 = 7p where p is an integer.

If that is the case, then

x = 5p, then y = 5p-1. By having 2z+1 = 7p, we are forcing that p is an odd integer, so we have infinite solutions. For each value of p that is an odd integer, then x=5p and y=5p-1 is a solution to the problem

7 0
3 years ago
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