Your students need to understand the relationships among objects on a graph. You ask students to:

Graph the image of the figure after a dilation with a scale factor of 1/3 centered at (1, −2) . Use the polygon tool to graph th

brilliants [131]

Answer:

New image will have (2,1) , (-2,0) and (-2,-2) as new vertex.

Below is the graph.

Step-by-step explanation:

Given the triangle with points (4,7) , (-8,4) and (-8,-2) having dilation center at (1,-2) .

We have to dilate using a factor of 1/3 and graph the new image.

Let us find all the three points,

Formula,

New point = [old point - dilation center]* scale factor + dilation center

So,

For (4,7)

$[(4,7)- (1,-2)]*\frac{1}{3} + (1,-2)$

$[3,9]*\frac{1}{3} +(1,-2)$

$[1,3]+(1,-2)= (2,1)$

For (-8,4)

$[(-8,4)- (1,-2)]*\frac{1}{3} + (1,-2)$

$[-9,6]*\frac{1}{3} +(1,-2)$

$[-3,2]+(1,-2)= (-2,0)$

For (-8,-2)

$[(-8,-2)- (1,-2)]*\frac{1}{3} + (1,-2)$

$[-9,0]*\frac{1}{3} +(1,-2)$

$[-3,0]+(1,-2)= (-2,-2)$

Therefore these (2,1) , (-2,0) and (-2,-2) are the new vertices after dilation.

4 0

4 years ago

PLZ HELP ASAP SOLID GEOMETRY

hichkok12 [17]

I believe the answers can be narrowed down to A or D, it depends on which direction its moving in and at which location you desire to measure each.

4 0

3 years ago

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1

Sindrei [870]

Answer:

88

Step-by-step explanation:

88+100+90+87=365

365 divided by 4=91.25

the answer is 88

7 0

3 years ago

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HELP PLZ THIS IS TIMED WILL GIVE BRAINLIEST

OlgaM077 [116]

(x² +9) and g(x) are factors of f(x).
That is, (x² +9)(g(x)) = f(x).

The roots of (x² +9) are roots of f(x). They are 3i and -3i.

The factor (x² +9) has degree 2, so f(x) has degree at least 2.

We cannot say anything about the x- or y-intercepts based on this information.

Imaginary roots usually come in even numbers (2, 4, etc.) for the polynomials we study. The information given here does not support the idea of 3 imaginary roots for f(x).

6 0

3 years ago

You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu

stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

$C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}$

$C=3\pi r^{2}+ \frac{162 \pi}{r}$

We differentiate C with respect to r

C'= $6\pi r -\frac{162 \pi}{r^2}$

At the minimum cost, C'=0.

Next we solve C'=0 for r

$6\pi r -\frac{162 \pi}{r^2}=0$

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0

4 years ago

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