Answer:
see explanation
Step-by-step explanation:
Using the chain rule and the standard derivatives
Given
y = f(g(x)) , then
= f'(g(x)) × g'(x) ← chain rule
(tanx) = sec²x , (cotx) = - csc²x
(c)
y = tan = tan
= sec² × ( )
= sec² ×
= sec² ×
=
(d)
y = cot(1 + x)
= - csc²(1 + x) × (1 + x)
= - csc²(1 + x) × 1
= - csc²(1 + x)
Move all the variables to one side. You are allowed to make one side of the equation 0 if you need to.
Step-by-step explanation:
Answer:
x = 0, x = 1
Step-by-step explanation:
Both graphs correctly plot f(x).
Only the bottom graph correctly plots g(x).
The points of intersection of f(x) and g(x) are (0, -4) and (1, -2). The x-value of these points are x = 0 and x = 1. These are the values of x for which f(x) = g(x).
Answer:
its either c or d
Step-by-step explanation: