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3 years ago

11

What is the surface area of the regular pyramid below?

1 answer:

makkiz [27]3 years ago

4 0

D. 756 units^2

Step-by-step explanation:

there ya go :)

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Using the Pythagorean

miss Akunina [59]

Answer:

13.5 units

Step-by-step explanation:

<u>Use distance formula:</u>

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

<u>Substitute the coordinates:</u>

$d = \sqrt{(-3-7)^2+(-3-6)^2} =\sqrt{10^2+9^2} =\sqrt{181} =13.5$ rounded

4 0

2 years ago

Read 2 more answers

What decimal is represented by this expanded form?

Radda [10]

2*10000 is 20000.

Start your expanded form with 20000. Add 7000, add 400, add 9, add 0.3 and add 0.008:

27409.308 (answer)

6 0

3 years ago

Irrational numbers can never be precisely represented in decimal form. why?

Rus_ich [418]

Because irrational numbers are unpredictable. for example, you can write 0.25 in a fraction (1/4) because 1/4 is 1 divided by 4 which is 0.25. But you can never divide 2 numbers to get a decimal that never ends

5 0

4 years ago

Write the phrase as a unit rate. 452.5 miles on 12.5 gallons of gasoline.

vovangra [49]

452 miles on 12.5 gallons = 452 miles / 12.5 gallons

= 36.16 miles / gallon

8 0

3 years ago

A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl

lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

$m=\frac{y_2-y_1}{x_2-x_1 }$

<u>Slope of AB</u>

$m_{AB}=\frac{8-5}{1--5}$

$\Rightarrow m_{AB}=\frac{8-5}{1+5}$

$\Rightarrow m_{AB}=\frac{3}{6}$

$\Rightarrow m_{AB}=\frac{1}{2}$

<u>Slope of BC</u>

$m_{BC}=\frac{2-8}{4-1}$

$\Rightarrow m_{BC}=\frac{-6}{3}$

$\Rightarrow m_{BC}=-2$

<u>Slope of CD</u>

$m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-4}{-6}$

$\Rightarrow m_{CD}=\frac{2}{3}$

<u>Slope of AD</u>

$m_{AD}=\frac{-2-5}{-2--5}$

$\Rightarrow m_{AD}=\frac{-2-5}{-2+5}$

$\Rightarrow m_{AD}=\frac{-7}{3}$

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

$m_{AD} = \frac{-7}{3} \neq m_{BC}=-2$

$m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}$

<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

$m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1$

$m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1$

Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle

6 0

3 years ago