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3 years ago

Help me please!

Mathematics

1 answer:

kati45 [8]3 years ago

5 0

Answer:

(cost ---> length)

35 ---> 5

49 ---> 7

56 ---> 8

70 ---> 10

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Tessellation that use more than one type of regular polygon are called regular tessellations

NARA [144]

Answer:

FALSE

Step-by-step explanation:

A tessellation refest to a shape that is repeated over and over again covering a plane without any gaps or overlaps. The statement is false given that regular tessellations use only one polygon. Semi-regular tessellations are created with more than one type of regular polygon.

8 0

4 years ago

Read 2 more answers

I need to find the sum of this equation

Tresset [83]

Answer:

$\large\boxed{\dfrac{3s^2+19s-4}{(s-1)^2(s+5)}=\dfrac{3s^2+19s-4}{s^3+3s^2-9s+5}}$

Step-by-step explanation:

$s^2-2s+1=s^2-s-s+1=s(s-1)-1(s-1)=(s-1)(s-1)=(s-1)^2\\\\s^2+4s-5=s^2+5s-s-5=s(s+5)-1(s+5)=(s+5)(s-1)\\\\\text{Therefore}\ LCD\ \text{is}\ (s-1)^2(s+5).$

$\dfrac{3s}{s^2-2s+1}+\dfrac{4}{s^2+4s-5}=\dfrac{3s(s+5)}{(s-1)^2(s+5)}+\dfrac{4(s-1)}{(s-1)^2(s+5)}\\\\\text{use the distributive property}\\\\=\dfrac{(3s)(s)+(3s)(5)+(4)(s)+(4)(-1)}{(s-1)^2+(s+5)}=\dfrac{3s^2+15s+4s-4}{(s-1)^2(s+5)}\\\\=\dfrac{3s^2+19s-4}{(s-1)^2(s+5)}$

4 0

3 years ago

Please help thank you

Butoxors [25]

Answer:

it might go like A= 12 B= 0 C = -6

8 0

3 years ago

What is the value of x in the triangle?

Firdavs [7]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The value of x is ~

$\boxed{5 \sqrt{3} }$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

The Triangle stated in the diagram is a right angled Triangle, so

$\tan(30) = \dfrac{x}{15}$

$\dfrac{1}{ \sqrt{3} } = \dfrac{x}{15}$

$x = \dfrac{15}{ \sqrt{3} }$

$x = 5 \sqrt{3}$

4 0

3 years ago

The radius of a sphere is 7 meters what is the circle's area

Pie

★ Given :

$\begin{lgathered}\bullet\:\:\textsf{Radius of circle = \textbf{7 meter}}\end{lgathered}$

$\rule{130}1$

★ Digram :

$\setlength{\unitlength}{1mm}\begin{picture}(50,55)\thicklines\qbezier(25.000,10.000)(33.284,10.000)(39.142,15.858)\qbezier(39.142,15.858)(45.000,21.716)(45.000,30.000)\qbezier(45.000,30.000)(45.000,38.284)(39.142,44.142)\qbezier(39.142,44.142)(33.284,50.000)(25.000,50.000)\qbezier(25.000,50.000)(16.716,50.000)(10.858,44.142)\qbezier(10.858,44.142)( 5.000,38.284)( 5.000,30.000)\qbezier( 5.000,30.000)( 5.000,21.716)(10.858,15.858)\qbezier(10.858,15.858)(16.716,10.000)(25.000,10.000)\put(25,30){\line(5,0){20}}\put(25,30){\circle*{1}}\put(29,26){\sf\large{7 m}}\end{picture}$

$\rule{130}1$

★ Solution :

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies\sf Area\:of\:circle = \pi r^2 \\\\\\:\implies\sf Area\:of\:circle = \dfrac{22}{\cancel{7}} \times \cancel{7} \times 7\\\\\\:\implies\sf Area\:of\:circle = 22 \times 7\\\\\\:\implies\sf Area\:of\:circle = 154 m^{2}$

⠀

$\therefore\:\underline{\textsf{Area of circle is \textbf{154}} \:\sf{m^2}}.$

$\rule{170}{2}$

7 0

3 years ago