Answer:
y = (1/5)x² or y = x²/5
Step-by-step explanation:
We have the function f(x) = ax² and are given that the point (5,5) is on the parabola. We need to find 'a'. f(x) can be replaced with 'y', so we can rewrite the equation as...
y = ax²
We know that when x = 5, y = 5, so we have
5 = a(5²) now simplify...
5 = 25a
5/25 = a
1/5 = a, so our equation becomes
(1/5)x² or x²/5 (the expressions are equal)
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.



The length of AD is



The length of BC is:



The length of CD is



Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB
Slope of BC 
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus
Answer:
what? okie but...
Thxs for the free points but thank you for being kind person may god bless ur day - p.s mark me branily and another blessing will come ur way! (x-<)
Step-by-step explanation:
[Rewritten and Fixed]
Joint relative frequency is the ratio of the frequency in a certain category and the total number of data points in that category.
Here is the equation: x+(x+20) = 120
Since you can't combine anything yet, its x+x+20=120
You need to get x by itself
Minus 20 from both sides
Its x+x=100 now
Combine the x's which is now 2x
Now divide 100 by 2 which is 50
x=50
---------------
Lets check:
50+(50+20)=120
Now combine the numbers in the parentheses
Its now 50+70=120
50+70=120 and 70-50=20
As you can see, he ran 50 minutes the first day and 70 minutes the second day