Answer:
The execution resumes in the finally block if one exists or otherwise from the next statement following the try...catch block.
Explanation:
Once an exception has been thrown and caught in the code, the execution continues with the statements in the finally block if one exists. If there is no finally block defined then execution resumes from the next statement following the try... catch block. For example:
try{
//An exception is raised
}
catch (Exception e){
//Exception is handled
}
System.out.println("After try...catch");
In this code segment, the next statement to be executed after catch is the System.out.println();
Answer:
I believe it is the NIC manufacturer and the serial number of the NIC
Explanation:
Answer:
header
title
nav
main
Explanation:
An HTML element is a component of an HTML document that tells a web browser how to structure and interpret a part of a HTML document. so without the basic element the browser will not be well structured
Answer:
C++ programming language (code) was used or applied in prompting a user to enter he number of series components in a system and the MTBFs for each component and then calculates the overall MTBF for the system using a FOR or a WHILE structure (loop).
Explanation:
Solution
THE CODE
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int key;
// do while loop to run the program up to user wants to quit "to quit enter any number except 1 "
do
{
int n,i=0,mtbf[100]; //declaring array to store the mtbf values of the n components
float result=0,result1;
cout<<"\n Enter number of components";
cin>>n;
while(i<n) // reading mtbf values into the array
{
cout<<"\n Enter MTBF(Mean time between failure)==>";
cin>>mtbf[i];
i++;
}
i=0;
while(i<n) //in this while loop first i calculate the denominator part i.e (1/mtbf[i])+(1/mtbf[i])...
{
result+=(1.0/mtbf[i]);
i++;
}
result1=1/result; //this value calculate the total MTBF of the system
cout<<"\n The MTBF of SYSTEM is\t"<<result1;
cout<<"\n Another system to check? enter 1 for yes";
cin>>key;
}while(key==1);
}
Answer:
Giving that: The following is a sequence of undo-log records written by 2 transactions T and U:
< START T >;
< T,A,10 >;
< START U >;
< U, B, 20 >;
< T, C, 30 >;
< U, D, 40 >;
< Commit U >;
< T, E, 50 >;
< Commit T >;
1. < START U >
Recovery action in this case will be undo(-1) and undo(0). All restored to its original Value
log records < T, A, 10 >, < T, abort >; as written out
2. < T, E, 50 >
Recovery action in this case will be undo(8) and redo(0). A and C is restored to its original value, B and D are set to 20 and 40
log records <T, C, 30 >, < T, A, 10 >, < T, abort > are written out
3. < Commit T >
Recovery action in this case will be redo(7) and redo(4). A and C are set to 10 and 30, B and D are set to 20 and 40