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3 years ago

Can someone pls help me … I really need help

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

Answer:

It's the last one!

Step-by-step explanation:

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3 years ago

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Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

Sladkaya [172]

Answer:

The null hypothesis is $H_0: \mu = 2.5$ .

The alternative hypothesis is $H_1: \mu > 2.5$

Step-by-step explanation:

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years.

At the null hypothesis, we test if the mean is of 2.5 years, that is:

$H_0: \mu = 2.5$

A study was then done to see if the mean time has increased in the new century.

At the alternative hypothesis, we test if the mean has increased, that is, if it is above 2.5 years. So

$H_1: \mu > 2.5$

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3 years ago

Joseph needs 345 cement blocks to build a wall 40 cm thick. He needs 205 cement blocks to build a wall 25 cm thick. Each block c

IrinaVladis [17]

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Answer:

$105

Step-by-step explanation:

The thicker wall takes 345 -205 = 140 more blocks. Each of those costs $0.75, so the added blocks will cost ...

140 × $0.75 = $105

The thicker wall will cost $105 more.

7 0

3 years ago

The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu

Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t - 5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

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3 years ago

Cd+de=ef+de by the

meriva

Is this chemistry, their are many apps online that do you it automatically for u

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3 years ago