Please help me!!!!!
1 answer:
Answer:
y = - (x - 5)² + 7
Step-by-step explanation:
The equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (5, 7 ) , then
y = a(x - 5)² + 7
To find a substitute (10, - 3 ) into the equation
- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )
- 10 = 5²a = 25a ( divide both sides by 25 )
= a , that is
a = -
y = - (x - 5)² + 7 ← in vertex form
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Hi again!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!
The zeros are the values of x. This is where the graph intersects the x - axis. In order to find the zeros, replace y with 0 and solve for x.
The answer is x = 0, -π, 4
I am not sure what grade are you or the level, but for me, they sometimes asked me to find their multiplicities as well
The multiplicity of a root is the number of times the root appears.
So, the answer are
x = 0 and the multiplicity of 2
x = -π and the multiplicity of 3
x = 4 and the multiplicity of 2
Good luck with your studies!