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dlinn [17]
3 years ago
5

Help me please on question one and two

Mathematics
1 answer:
pav-90 [236]3 years ago
4 0

Answer:

can you show me a better picture your problems are cut off

Step-by-step explanation:

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Please help! image below with question
inysia [295]

Answer:

scale factor = \frac{1}{2}

Step-by-step explanation:

To calculate the scale factor compare the ratio of corresponding sides, image to original.

Comparing the base of both triangles

Figure A = 6 and Figure B = 3

scale factor from A to B is

k = \frac{3}{6} = \frac{1}{2}

7 0
3 years ago
Read 2 more answers
Find the exact values of the six trigonometric functions of the angle(theta)
Vedmedyk [2.9K]
X is 8 y is 6 , sin (y/r) r=10. x^2+y^2 = r^2. cos(x/r) tan (y/x) the other 3 are probably cosecant secant and cotangent just do the inverse (flip them) r/x etc..
3 0
4 years ago
Consider the bank account transactions shown. Which transaction will create the biggest change in the bank account balance?
arsen [322]
A withdrawal of $60

60 is the largest number therefore it’ll make the biggest impact because you’re loosing the most money
4 0
4 years ago
Is 7 a solutions to the compound inequality "-3 < x < 6 "
Angelina_Jolie [31]

7 cannot be the solution of compound inequality -3 < x < 6

Step-by-step explanation:

We need to find if  7 a solutions to the compound inequality -3 < x < 6

The compound inequality -3 < x < 6 states that the value of x can be greater than -3 but less than 6

Since 7 is greater than 6 so, 7 can't be the solution of compound inequality.

So, 7 cannot be the solution of compound inequality -3 < x < 6

Learn more about compound inequality at:

brainly.com/question/1465430

brainly.com/question/1858613

brainly.com/question/6703816

Keywords: compound inequality

#learnwithBrainly

4 0
3 years ago
This circle is centered at the origin, and the length of its radius is 8. What is
Kitty [74]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x² + y² = 64

____________________________________

\large \tt Solution  \: :

Standard equation of circle is :

\qquad \tt \rightarrow \: (x - h) {}^{2}  + (y - k) {}^{2}  =  {r}^{2}

  • \textsf{h = x - coordinate of centre of circle}

  • \textsf{k = y - coordinate of centre of circle}

  • \textsf{r = radius= 8}

Since the circle is centered at origin, h = k = 0

\qquad \tt \rightarrow \: (x - 0) {}^{2}  + (y - 0) {}^{2}  =  {8}^{2}

\qquad \tt \rightarrow \:  {x}^{2}  +  {y}^{2} = 64

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
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