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Lesechka [4]
2 years ago
5

Um yeah so ignore the blue circles. I need your helpp ty <3

Mathematics
2 answers:
Archy [21]2 years ago
6 0

Answer:

15, 6,0, 11, 7

I'm not sure but hope it helps

Step-by-step explanation:

y=8+7

=15

y=-1+7

=6

y=-7+7

=0

y=4+7

=11

y=0+7

=7

Natasha_Volkova [10]2 years ago
3 0

Answer:

where is the diagram u there is must must graphic of this or diagram

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Jill converted the equation of the line 15x-4y=-2 into slope-intercept form and found the slope and y-intercept of the line
slega [8]

Answer:

She got the sign of the slope wrong

Step-by-step explanation:

She did \frac{-4y}{-4} = \frac{-2-15x}{-4} and turned that into \frac{-2}{-4}-\frac{-15x}{-4}, which is wrong, because she did the negative twice. Therefore, she mixed up the sign of the slope.

Please mark brainliest if this helped you!

7 0
3 years ago
What is h(x)=4x+1 if the value of h is (-3)
Reil [10]

Step-by-step explanation:

Salna, it is a question about simple function

Substitute x= -3 into function,

h(-3) = 4 x (-3) + 1

= -11

5 0
3 years ago
If 9x is an odd integer, represent the next odd integer as the algebraic expression in x.
Luba_88 [7]
Any odd integer can be expressed as 2n+1, for some integer n.

The next odd integer, after 2n+1, is 2n+1+2=2n+3



thus 9x=2n+1, means that 9x-1=2n,   so n=(9x-1)/2

the next odd number after 2n+1 is 2n+3= 2* (9x-1)/2+3=9x-1+3=9x+2


Remark : this result could also have been found directly.


Answer: 9x+2
8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST
jekas [21]

Answer:

10

Step-by-step explanation:

√81 = 9   (9+9-4*2)

4 * 2 = 8  (9+9-8)

9 + 9 = 18 (18 - 8)

18 - 8 = 10

7 0
2 years ago
Read 2 more answers
#7-9 please help with an explanation,, will mark brainliest
Mandarinka [93]

Answers:

<h2>7. 12</h2><h2>8. -√18</h2><h2>9. √220</h2>

Step-by-step explanation:

To find out which is greater, we must eliminate the radical symbol.

#7

\sqrt{88} = 9.38083151965

9.4 < 12

#8

-\sqrt{18} = -4.24264068712

-4.2 > -6

#9

\sqrt{220} = 14.8323969742

14.5 < 14.8

I'm always happy to help :)

8 0
3 years ago
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