A phenotype is the physical appearance of a characteristic.
A genotype is the code for that characteristic.
Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
If a 10 year old child is diagnosed with acute glomerulonephritis and admitted to the pediatric unit, the nurse should TAKE THE VITAL SIGNS EVERY 4 HOURS AND OBTAIN THE DAILY WEIGHT OF THE CHILD.
Glomerulonephritis is a disease of kidney where the glomeruli are injured. It is very important to take measure the vital signs such as taking blood pressure of the child because in this disease acute renal failure might occur that hampers the vital functions of the body. Weighing the child everyday is also important because this helps to know the fluid status in the body.
It is like a barrier, or wall. It helps infection and bacteria stay out. It can also help you indicate whether you are getting infection in the inside of your body. if you're skin is inflamed, that is a sign of disease or infection.
I hope this helped you!
Brainliest answer is always appreciated!<span />
Answer:
Let:
Y = Yellow R = Round
y = green r = Wrinkled
If you look at the F1 generation, all the plants are round and yellow, so these are the dominant traits and each offspring is heterozygous for both traits. The cross for the F2 generation would then be:
<em>YyRr x YyRr</em>
In a Punnett it would look like the attached picture.
For the forked-line diagram, first you will need to know the gentypes and ratio of each trait in a monohybrid cross. Select one trait, and then branch each gentype to the next trait, linking it with each possible genotype combination of the monohybrid cross.
Attached is a picture of the Forked Branch diagram for this cross.
