All categories

2 years ago

The hanger image below represents a balanced equation.

Mathematics

1 answer:

Allushta [10]2 years ago

5 0

Answer:

2x =3

The hanger image given in the figure represents balanced equation.

Then we have to write an equation to represent the image.

In balanced form left side = right side

x + x = 1 + 1 + 1

2x = 3

You might be interested in

Which number produces a rational number when multiplied by 1/5

valentinak56 [21]

Answer:

-2/3

Step-by-step explanation:

Gimme brainliest if I'm correct

3 0

2 years ago

Read 2 more answers

Morgan's hourly salary is $8. If Morgan works more than 40 hours a week, then Morgan gets overtime pay at 1 and 1/2 times the re

Svetlanka [38]

9514 1404 393

Answer:

$96

Step-by-step explanation:

Morgan worked 48 -40 = 8 hours of overtime. The pay for each of those hours is 1.5×$8 = $12.

Morgan earned (8 h)×($12/h) = $96 in overtime pay.

3 0

3 years ago

PLZZ HELP<br> What is the solution to: y=-2x+7 and y=3x+2?

Anit [1.1K]

Please see the pic, I'd solved in it.

4 0

3 years ago

Read 2 more answers

Please solve in the next 10 minutes pleaseeee

Alex787 [66]

Answer:

43.82 mph

266.67 feet

Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

l = Length of skid mark

If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

80 = √30*0.8*l

80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

6 0

3 years ago

Pleasantburg has a population growth model of P(t)=at2+bt+P0 where P0 is the initial population. Suppose that the future populat

yulyashka [42]

Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

$P(t) = 0.8t^{2} + 6t + 19000$

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

$P(t) = 0.8t^{2} + 6t + 19000$

$0.8t^{2} + 6t + 19000 = 34200$

$0.8t^{2} + 6t - 15200 = 0$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$0.8t^{2} + 6t - 15200 = 0$

So $a = 0.8, b = 6, c = -15200$

Then

$\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356$

$t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14$

$t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64$

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

6 0

3 years ago