All categories

2 years ago

Exit Ticket

Mathematics

1 answer:

miskamm [114]2 years ago

4 0

Throughout this, I'm assuming that the scale is: 1 square = 1

Not 100% sure if my answers are correct.

Question 1:

The x coordinate must be 2 and the y coordinate must be -1.

Question 2:

The x coordinate would be -2 and the y coordinate would be -1.

You might be interested in

523 x = 523 x = last one

Sphinxa [80]

Answer:

X has an infinite number of solutions

0 = 0

Step-by-step explanation:

Hey there!

Given,

523x = 523x

Simplify

523x = 523x

-523x to both sides

0 = 0

So x has an infinite number of solutions.

Hope this helps :)

5 0

3 years ago

Read 2 more answers

What is the measure of ABC?

MaRussiya [10]

Answer:

D i think

Step-by-step explanation:

3 0

2 years ago

The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth

Art [367]

Answer:

a) $N_0=250\; k=0.15$

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies $t=0$ . And $N(0)=N_0$ . The process is:

$N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250$

b) After 2 days means $t=48$ . So, we just replace and operate:

$N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}$

c) $N(t_1)=4000; \;t_1=?$

$N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\ \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h$

d) $t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)$

$N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h$

6 0

3 years ago

Consider a line passing through the points A(–28, –13) and B(28, 15). Type the y-value for the point C(–24, y) to ensure that po

Nostrana [21]

Step-by-step explanation:

$\frac{y_2-y_1}{x_2-x_1}=\frac{15-(-13)}{28-(-28)}\\=\frac{28}{2(28)}\\\therefore\ m=\frac{1}{2}\\\frac{y-y_1}{xl-x_1}=m]\\\frac{y+13}{x+28}=\frac{1}{2}\\2y+26=x+28\\2y=x+2\\ y=\frac{1}{2}x+1$

In order to find y for point C on AB, substitute point C in line equation if AB.

$y=\frac{1}{2}(-24)+1\\\therefore y=-12+1=11\\\therefore C(-24, -11)$

7 0

3 years ago

Find the coordinates of the other endpoint when you are given the midpoint (point M) and one of the endpoints (point P). P = (5,

Rus_ich [418]

5+x/2=8
5+x=16
x=11
6+y/2=2
6+y=4
y=-2
(11,-2)

5 0

3 years ago

Read 2 more answers