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8_murik_8 [283]
3 years ago
14

Here is a tunnel for a toy train. The diagram shows the cross section of the tunnel. AD is a semicircular arc of radius is 10cm.

BC is a semicircular arc of radius 8cm. The length of the tunnel is 30cm. Work out the total area of all six faces of the tunnel. Give your answer in terms of π.

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer: ??

Step-by-step explanation:

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Which line is the best model for the data in the scatter plot? A scatterplot with an x axis labeled, variable A from twenty to s
Firlakuza [10]

The line which is the best model for the data in a scatter plot is: D. A scatterplot with an x axis labeled, variable A from twenty to sixty in increments of ten and the y axis labeled, variable B from twenty to forty in increments of five with a negative trend line through the middle of eight points.

<h3>What is a scatter plot?</h3>

A scatter plot can be defined as a graph which uses Cartesian coordinates (x-axis and y-axis) to display the values of two (2) variables, with the resulting points revealing any correlation between the data.

<h3>What is a trend line?</h3>

A trend line refers to an statistical (analytical) tool that is used in conjunction with a scatter plot, so as to determine whether or not there's any correlation between a data.

For example, a scatterplot with an x-axis with its points ranging from twenty (20) to sixty (60) in increments of ten (10) while the y-axis has  its points ranging from twenty (20) to forty (40) in increments of five (5) with a negative trend line through the middle of eight (8) points i.e above and below the trend line.

Read more on scatterplot here: brainly.com/question/6592115

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2 years ago
What is |9|? <br> a. –9 <br> b. 0 <br> c. 9 <br> d. 18 u
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The answer to an absolute value can be positive or negative but a negative can not be inside the absolute value bars.
8 0
3 years ago
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How would you calculate the area and perimeter of 3yd 6yd 5yd 10yds
spayn [35]
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15

That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
5 * 6 = 30

Conclusion for Area: After adding the results the answer should be 45.

The perimeter is solely adding all the sides together. You have a 10, two 5's, one 6, and two 3's. Add this together:

10 + 5 + 5 + 6 + 3 + 3 = 32

Conclusion for Perimeter: So the perimeter would be 32.

I hope this helps in someway, have a great rest of your day! ^ ^
| | Ghostgate | |
3 0
3 years ago
When I sit and watch my students take exams, I often think to myself "I wonder if students with bright calculators are impacted
hodyreva [135]

Answer:

There is a difference between the two means.

Step-by-step explanation:

The hypothesis can be defined as:

<em>H₀</em>: The mean exam scores of my SAT 215 students with colorful calculators are same as the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: The mean exam scores of my SAT 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

Assume that the significance level of the test is, <em>α</em> = 0.05. Also assuming that the population variances are equal.

The decision rule:

A 95% confidence interval for mean difference can be used to determine the result of the hypothesis test. If the 95% confidence interval contains the null hypothesis value, i.e. 0 then the null hypothesis will not be rejected.

The 95% confidence interval for mean difference is:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

Compute the pooled standard deviation as follows:

S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}} {n_{1}+n_{2}-2}}}=\sqrt{\frac{(49-1)(4.7)^{2}+(38-1)(5.7)^{2}}{49+38-2}}=5.16

The critical value of <em>t</em> is:

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (49+38-2)}=t_{0.025, 85}=1.984

*Use a <em>t</em>-table.

Compute the 95% confidence interval for mean difference as follows:

CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times \sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}

     =(84-87)\pm 1.984\times 5.16\times \sqrt{\frac{1}{49}+\frac{1}{38}}

     =-3\pm 2.133\\=(-5.133, -0.867)\\\approx(-5.13, -0.87)

The 95% confidence interval for mean difference is (-5.13, -0.87).

The confidence interval does not contains the value 0. This implies that the null hypothesis will be rejected at 5% level of significance.

Hence, concluding that the mean exam scores of my STA 215 students with colorful calculators are different than the mean scores of my STA 215 students with plain black calculators.

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4 years ago
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iVinArrow [24]
The answer is B (-2,2)
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4 years ago
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