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lesantik [10]
2 years ago
13

Is (-2, 11) a solution to the following system of equations: y = 2x - 5, y = 4x - 3? Explain.​

Mathematics
1 answer:
diamong [38]2 years ago
6 0

Answer:no

Step-by-step explanation:

The answer is (-1,-7)

Y=4x-3

(4x-3)-2x=-5

2x=-2

X=-1

Y=4(-1)-3=

-7

(-1,-7)

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434/7 as rate will it be 62 or 6:2
Licemer1 [7]

Answer:

I think it's 62.

Hope this helps!

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4 years ago
Leroi and Sylvia both put $100 in a savings account. Leroi decides he will put in an additional $10 each week. Sylvia decides to
kati45 [8]
Leroi’s account

$100
After first deposit = $100+$10=$110
After second deposit= $110 + $10 = $120


Sylvia’s account

$100
10% of $100 is $10
After first deposit = $100+ $10 = $110
10% of $110 = $11
After second deposit = $110 + $11 = $121

Therefore after their first deposit, both will have the same value in their accounts.
But after the second deposit, Sylvia will have 1$ more in her account than Leroi.
7 0
3 years ago
Read 2 more answers
a department store buys 300 shirts at a cost of $5,400 and sells them at a selling price of $20 each. Find the markup price
Romashka-Z-Leto [24]

It is $2 markup price.

8 0
3 years ago
Which best describe how to solve the equation below 35x=88
Fofino [41]

x=2.514

To get this andeer you must divide 88 and 35 by 35 to make sure that only x and 2.514 are left over.

6 0
2 years ago
In the New York State number lottery, you pay $1 and pick a number from 000-999. If your number comes up, you win $500, which is
slava [35]

Answer:

Expected value of profit is ≅ $15.80

Step-by-step explanation:

from the Question,

Let the variable X represents the expected value of profit. X is called as random variable because picking a number from 000-999 digits is a Random process.

P(win) = 0.001

So, P(lose) = 1-0.001=0.999

Suppose that,

we really want to win this lottery. so we can go to the store and spend $1000 to buy all ticket (from 000 - 999). This would ensure your winning of $500 with one of the tickets (for a $499 profit), but the other 999 would be  losers (for a $999 loss).

What would be your average winnings on a per-ticket basis?

               u = E(x) =∑x\times P(x)

                  = 499\times0.0001+ (-1)\times0.999

                  = -0.50

Here,

Standard deviation of the expected winnings

           V (X) =  ∑(x-u)^{2} \times P(x)

                     =   ∑ (499-(-0.50))^{2} \times 0.001 + (-1-(-0.50))^{2} \times 0.999

                     = 249.75

Taking square root of the variance to get the standard deviation:

               SD(x) = \sqrt{249.75}

                        ≅ $15.80

Hence

The expected value of profit is ≅ $15.80

6 0
3 years ago
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