The slope is 2
y2-y1/x2-x1
(9,-1) (4-11)
-1+11/9-4
10/5
2
Answer:
![\mathbf{=\frac{2x-1}{2x}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%3D%5Cfrac%7B2x-1%7D%7B2x%7D%7D)
Step-by-step explanation:
![1-\frac{1}{x}\div2](https://tex.z-dn.net/?f=1-%5Cfrac%7B1%7D%7Bx%7D%5Cdiv2)
To divide a fraction by a number just reciprocate the number which is there after division sign as done here. If there is one more fraction then reciprocate the fraction.
![=1-\frac{1}{x}\times\frac{1}{2}](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7B1%7D%7Bx%7D%5Ctimes%5Cfrac%7B1%7D%7B2%7D)
![=1-\frac{1}{2x}](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7B1%7D%7B2x%7D)
∴ ![=\frac{2x-1}{2x}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2x-1%7D%7B2x%7D)
(NOTE : <em>Reciprocating means interchanging the numerator and denominator of that fraction</em>.)
Answer:
Step-by-step explanation:
For a triangle the area is
![A=\frac{1}{2}bh](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7Dbh)
If our triangle is isosceles and the 2 congruent sides each measure 4 and they include an angle of 40 degrees, let's say that the vertex angle is 40 and the sides that are not the base each measure 4. If we drop an altitude from the vertex to the base, we cut the triangle into 2 right triangles, with the vertex angle being 20 degrees and the hypotenuse being 4. To find the base, then, which is opposite the angle, we use the sin ratio:
and
4sin(20) = b so
b = 1.368
But we need the whole base, and that is only half of it. So
2b = 2.736
To find the height, which is adjacent to the angle, we use the cos ratio:
and
4cos(20) = h so
h = 3.759
Now we have enough info to find the area of the triangle using the triangle area formula from above:
and
A = 5 meters squared.
Rectangular prism area: 2(wl+hl+hw)
Cylinder area: 2πrh+2πr squared.
Sphere area: 4πr squared.
Cube- 2((4*3)+(5*3)+(5*4)). 2(12+15+20). 2(47). 94.
Cylinder- approximately 100.53.
Sphere- approximately 50.27
94+100.53+50.27= 245.23.
Which is around D so I would go with D. They must have approxicized it a little differently than me.