Answer:
Maximum area possible
f(max) = 3906,25 ft²
Dimensions:
a = 62,5 ft
w = 62,5 ft
Step-by-step explanation:
Perimeter of the rectangular fencing P = 250 feet
And sides of the rectangle a and w (width of rectangle)
Then
A = a*w
2a + 2w = 250 ⇒ a = (250 -2w)/ 2 ⇒ a = 125 - w
f(w) = (125 - w ) *w f(w) = 125w - w²
Taking derivatives both sides of the equation
f´(w) = 125 - 2w f´(w) = 0 125 - 2w = 0
w = 125/2
w = 62,5 ft ⇒ a = 125 - 62,5
a = 62,5 ft
f(max) = ( 62,5)²
f(max) = 3906,25 ft²
3+2x
i think that would be the answer smol child
Hey there!
2^2 + 5 + 50 ÷ 2(5)
2^2 = 2 • 2 = 4
4 + 5 + 50 ÷ 2(5)
4 + 5 = 9
9 + 50 ÷ 2(5)
50 ÷ 2 = 25
9 + 25(5)
25(5) = 125
9 + 125
= 134
Answer: 134 ☑️
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
The answer depends on where the ship starts from. If it starts on the equator, the answer is 459.938 miles.
If it starts at 70° N, then the distance is 446.084 miles.
And if the ship is on a flat earth, the distance is 459.954 miles (very close to the distance on a round Earth starting at the equator). Hope this helps!