T the woman row part way at an angle Θ to the diameter,
<span>and walk along the arc for the rest of the way. </span>
<span>since the triangle on the diameter is right angled, angle subtended at the centre by the arc walked will be 2Θ </span>
<span>distance rowed is 2rcosΘ = 4cosΘ </span>
<span>and length of the arc jogged = r•2Θ = 4Θ, Θ in radians, </span>
<span>so T(Θ) = 4cosΘ/5 + 4Θ/10 </span>
<span>= 0.8cosΘ + 0.4Θ </span>
<span>T'(Θ) = -0.8sinΘ + 0.4 </span>
<span>but T"(Θ) = -0.8cosΘ, so setting T'(Θ) to 0 will give a MAXIMA </span>
<span>so minimum time has to be at one of the 2 extrema (Θ=0 or pi/2) </span>
<span>T(0) = 0.8 </span>
<span>T(pi/2) = 0.4pi/2, < T(0) </span>
<span>so least time = 0.4pi/2 hrs </span>
0 because 10 - 10 equals 0
Find the lowest common denominator, which would be 30.
You would get -35/30 + 42/30
Which equals 7/30
7/30 is your answer
If you asking for a random one then heres a rand om one: Y^3–2 or y^4+7
Answer:
a) 360 mice
b) 364 mice
Step-by-step explanation:
Assume :
A = number of infected mice , B = number of non-infected mice
P( infected mice overcoming infection ) = 70% = 0.7
P ( Infected mice not overcoming infection ) = 1 - 0.7 = 0.3
P( mice becoming infected ) = 40% = 0.4
P ( mice not becoming infected ) = 1 - 0.4 = 0.6
Number of infected mice = 400
Number of non-infected mice = 1000 - 400 = 600
step 1 ; express the probabilities in matrix form
step 2 : multiply the matrix above to determine the number of mice that will be infected
<u>a) For next week </u>
PX =
<em>i.e. 360 mice will get infected next week </em>
next 2 week = P ( PX )
= * =
<u>b) In 3 weeks time </u>
P ( P(PX) = *
=
i.e. 364 mice will get infected in 3 weeks time