Answer:
x=12.5
y=10
Step-by-step explanation:
Properties of rectangle:
- Opposite sides are congruent
- All angles are right angles
- Diagonals bisect each other
- Diagonals are of equal length
so from the properties we came to know that diagonals bisects each other and diagonals are of equal length
Given Rectangle RSUT has diagonals that meet at point X.
⇒![RX=SX=UX=TX=\frac{1}{2}RU=\frac{1}{2}ST](https://tex.z-dn.net/?f=RX%3DSX%3DUX%3DTX%3D%5Cfrac%7B1%7D%7B2%7DRU%3D%5Cfrac%7B1%7D%7B2%7DST)
⇒![RX=\frac{1}{2}ST](https://tex.z-dn.net/?f=RX%3D%5Cfrac%7B1%7D%7B2%7DST)
⇒![4x=\frac{1}{2}(100)](https://tex.z-dn.net/?f=4x%3D%5Cfrac%7B1%7D%7B2%7D%28100%29)
⇒![x=12.5](https://tex.z-dn.net/?f=x%3D12.5)
Also ![XU=RX](https://tex.z-dn.net/?f=XU%3DRX)
⇒![(4)(12.5)=5y](https://tex.z-dn.net/?f=%284%29%2812.5%29%3D5y)
⇒![5y=50](https://tex.z-dn.net/?f=5y%3D50)
⇒![y=10](https://tex.z-dn.net/?f=y%3D10)
Answer:
angle coa is 90°.
angle coa=angle boa+ angle boc
90°=79°- <boc
90°-79°=<boc
11°=<boc
Answer:
b+5 ≥ 12
Step-by-step explanation:
Let the additional bushes to be planted be represented by a variable b
Since Tamara already planted 5 bushes, 5 will be a constant in the inequality ;
So,
b+5 ≥ 12 will be the inequality used to find number of bushes.
On the Y-axis you graph -1. From there you go up three and two to the right and keep following that pattern
For a cylinder
![V_\textrm{cyl} = \pi r^2 h](https://tex.z-dn.net/?f=V_%5Ctextrm%7Bcyl%7D%20%3D%20%5Cpi%20r%5E2%20h)
Since ![h = 2r](https://tex.z-dn.net/?f=h%20%3D%202r)
![V_\textrm{cyl} = 2 \pi r^3](https://tex.z-dn.net/?f=V_%5Ctextrm%7Bcyl%7D%20%3D%202%20%5Cpi%20r%5E3%20)
We know that's 64 cubic meters,
![64 = 2 \pi r^3](https://tex.z-dn.net/?f=%2064%20%3D%202%20%5Cpi%20r%5E3)
The sphere's volume is
![V = \frac 4 3 \pi r^3 = \frac 2 3 (2\pi r^3) = \frac 2 3 (64) = \dfrac{128}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%204%203%20%5Cpi%20r%5E3%20%3D%20%5Cfrac%202%203%20%282%5Cpi%20r%5E3%29%20%3D%20%5Cfrac%202%203%20%2864%29%20%3D%20%5Cdfrac%7B128%7D%7B3%7D)
Answer: 128/3 cubic meters
That may be that choice peeking out at the bottom; can't really tell