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yan [13]
3 years ago
11

Which statement is correct? The domain of the function is all real numbers greater than or equal to 0. The range of the function

is all real numbers greater than or equal to −1. The range of the function is all real numbers less than or equal to 0. The domain of the function is all real numbers less than or equal to 0.
Mathematics
1 answer:
rusak2 [61]3 years ago
8 0

Answer: In Functions and Function Notation, we were introduced to the concepts of domain and range. In this section, we will practice determining domains and ranges for specific functions. Keep in mind that, in determining domains and ranges, we need to consider what is physically possible or meaningful in real-world examples, such as tickets sales and year in the horror movie example above. We also need to consider what is mathematically permitted. For example, we cannot include any input value that leads us to take an even root of a negative number if the domain and range consist of real numbers. Or in a function expressed as a formula, we cannot include any input value in the domain that would lead us to divide by 0.

Step-by-step explanation:

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Two walls of a canyon form the walls of a steady flowing river. From a point on the shorter wall, the angle of elevation to the
Sunny_sXe [5.5K]

Answer:

x is approximately 226.3 feet

y is approximately 308.6 feet

z is approximately 226.3 feet

Step-by-step explanation:

The given parameters of the walls are;

The angle of elevation from the top of the shorter wall to the top of the opposing wall, θ₁ = 20°

From the diagram, the angle of depression from the top of the shorter wall to the bottom of the opposing wall, θ₂ = 45°

The distance from the bottom of the shorter wall to the base of the opposing wall, l = 320 feet

x = The height of the shorter wall = l × sin(θ₂)

∴ x = 320 feet × sin(45°) = 320 feet × (√2)/2 = 160·√2 feet ≈ 226.3 feet

∴ x ≈ 226.3 feet

By observation, we have;

y = x + z × tan(θ₁)

Where;

z = l × cos(θ₂)

∴ y = 160·√2 + 320 × cos(45°) × tan(20°) ≈ 308.6

y ≈ 308.6 feet

z =  l × cos(θ₂)

∴  z = 320 × cos(45°) = 160·√2 ≈ 226.3

z ≈ 226.3 feet.

6 0
3 years ago
If the area is 228 square units, what is the value of x?
kow [346]
Sorry I don’t now the answer to this problem
4 0
3 years ago
3,1,4,5,4,n ; the mode is 4, find n​
zheka24 [161]

Answer:

3

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Which of these are equivalent to -11/4? choose all that apply
shusha [124]

Answers:

A. -11÷4

B. 11 ÷ (-4)

D. -11/4

E. 11/-4

Reasoning:

      In a fraction, it doesnt matter where the negative is. Since we have a single negative sign, our answer must also have a single negative. (2 negative signs will cancel each other out.)

5 0
3 years ago
1. A flower shop wishes to add the valuable Waimea orchid to its product list. They purchase a large shipment of bulbs from a su
AysviL [449]

Answer:

The concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to perform the hypothesis test.

The hypothesis is defined as:

<em>H</em>₀: There is no difference between the observed and expected value.

<em>Hₐ</em>: There is a difference between the observed and expected value.

The test statistic is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}

The total number of Waimea orchid bulbs is, 60.

7x + 5x + 4x + 4x = 60

20x = 60

x = 3

The expected number of Waimea orchid bulbs are:

Blue = 7 × 3 = 21

Red = 5 × 3 = 15

Violet = 4 × 3 = 12

Orange = 4 × 3 = 12

Consider the table provided.

The test statistic value is:

\chi^{2}=\sum \frac{(O-E)^{2}}{E}=14.981

The decision rule:

The null hypothesis will be rejected if \chi^{2}\geq \chi^{2}_{\alpha, (k-1)}.

Compute the critical value as follows:

\chi^{2}_{0.05, (4-1)}= \chi^{2}_{0.05, (3)}=7.815

The test statistic value is 14.981.

\chi^{2}=14.981> \chi^{2}_{\alpha, (k-1)}=7.815

The null hypothesis will be rejected at 5% level of significance.

Conclusion:

As the null hypothesis was rejected it implies that there is a significant difference between the observed and expected value.

Thus, the concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

4 0
4 years ago
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