Question

I forgot the steps to [(2/3)^2•(2/3)^-1]^3

Answer 1

$\left[\left(\dfrac{2}{3}\right)^2\cdot\left(\dfrac{2}{3}\right)^{-1}\right]^3=\left[\left(\dfrac{2}{3}\right)^{2+(-1)}\right]^3\\\\=\left[\left(\dfrac{2}{3}\right)^1\right]^3=\left(\dfrac{2}{3}\right)^3=\dfrac{2^3}{3^3}=\dfrac{8}{27}\\\\Used:\\\\a^n\cdot a^m=a^{n+m}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$