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Reil [10]
2 years ago
5

A garden has only tomato and cucumber plants. There are 12 tomato plants and 5 cucumber plants.

Mathematics
2 answers:
Karolina [17]2 years ago
7 0

Answer:

5 17

Step-by-step explanation:

took the k12 test

Anastasy [175]2 years ago
6 0
The total number of plants are: 12 tomatoes + 5 cucumbers = 17 plants
The ratio of cucumbers plants to total plants is: 5 cucumbers to 17 plants total
So It can be expressed as: 5/17 or 5:17
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ANSWER IF YOU LOVE YOUR LORD!!!! Which graph represents the solution to: 2k+8<5k-1?
Leviafan [203]

Answer:

Third graph

Step-by-step explanation:

First, find the solution to the equation of inequality given.

2k + 8 < 5k - 1

Subtract 5k from both sides

2k + 8 - 5k < 5k - 1 - 5k

-3k + 8 < -1

Subtract 8 from both sides

-3k + 8 - 8 < -1 - 8

-3k < -9

Divide both sides by -3. (Note: < will change to > when dividing both sides with negative number)

\frac{-3k}{-3} > \frac{-9}{-3}

k > 3

The graph that will represent this solution will show that all values of k are greater than 3. 3 is not included as a solution. The "o" on top of the 3 on the number line won't be shaded to indicate that 3 is not included. And also, the arrow will point from 3 towards our right.

Therefore, the 3rd graph is the answer.

3 0
2 years ago
Maya spent 40% of her savings to pay for a bicycle that cost $60 how much was in her savings​
Ahat [919]

Answer:

$150

Step-by-step explanation:

First use a proportion to find the answer:

40/100=60/x

Now we solve for x

60*100=6,000

6,000 divided by 40= 150

x=150

Therefore the answer is $150

3 0
3 years ago
What is 25% of $8? $ Submit​
vekshin1

Answer:

2 dollars?

Step-by-step explanation:

8 divided by 4

3 0
2 years ago
Which table of values represents a linear function?
e-lub [12.9K]

Answer:

I don't know it's very hart

8 0
2 years ago
What are the solutions to this system of equations?
saveliy_v [14]

Answer:

A

Step-by-step explanation:

The solution is at the points of intersections of the graphs

The graphs intersect at (- 3, 0 ) and (2, 5 )  , then

solutions are (- 3, 0 ) and (2, 5 )

4 0
2 years ago
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