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Rzqust [24]
2 years ago
7

Help me plass plaas me

Mathematics
2 answers:
dezoksy [38]2 years ago
3 0

Answer:

it isn't really visible . do it right

Step-by-step explanation:

please mark me brainiest like my answer and follow me on this

MakcuM [25]2 years ago
3 0

Answer:

Option B

The answer is 15

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • Two points A(2, 10) and C(14, 1)
<h3><u>To </u><u>Find</u>;</h3>
  • The distance between A(2, 10) and C(14, 1)
<h3><u>Formula</u>;</h3>

AC = √[(x₂ – x₁)² + (y₂ – y₁)²]

Now,

x₁ = 2

x₂ = 14

y₁ = 10

y₂ = 1

AC = √[(x₂ – x₁)² + (y₂ – y₁)²]

AC = √[(14 – 2)² + (1 – 10)²]

AC = √[(12)² + (-9)²]

AC = √(144 + 81)

AC = √225

AC = 15 units

Thus, The distance between A(2, 10) and C(14, 1) is 15 units

 

<u>-TheUnknownScientist</u><u> 72</u>

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Simplify 7h^2+6h^2+5h^2+6h^2-h^2
iogann1982 [59]

Answer:

23h^2

Step-by-step explanation:

These are all like terms so we add/subtract them from left to right.

7h^2+6h^2+5h^2+6h^2-h^2

=   24h^2 - h^2

= 23h^2   (answer)

6 0
3 years ago
Please help with #6 need it very soon
gregori [183]

Answer:

If this is a proof then here is the answer.

Angle ABD is Congruent to Angle CBD = Given

Angle BDA is Congruent to Angle BDC = Given

Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector

Line Segment BD is Congruent to Line Segment BD = Reflexive Property

Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA

Step-by-step explanation:

Lucky for you, I just learned this also ;)


Since you are given your first two directions, put them down as GIVEN in the proof.

Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.

Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).

Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.

Hope this helped!


5 0
3 years ago
WHY is the work they give us online harder than the work we get at school? SOMEBODY PLEASE HELP :(
Dmitry_Shevchenko [17]

Answer:

First question

Circle A:

Radius:2.5 Diameter: 5 Circumference:15.71

Circle B:

Radius:12 Diameter:24 Circumference:75.4

Circle C:

Radius:32 Diameter:64 Circumference:201.06

Circle D:

Radius:42 Diameter:84 Circumference:263.89

Second one:

without Pi

1:81.68

2:37.7

3:263.89

with pi

1:26π

2:12π

3:84π

sorry, i have to keep looking back at the photo

for the last question i will be solving ok

8 0
3 years ago
SV is a midsegment of △RTU.<br> If TU=y+38 and SV=y–9, what is the value of y?
pav-90 [236]

Answer:

y = 56

Step-by-step explanation:

the midsegment SV is half the length of the side TU , that is

y - 9 = \frac{1}{2} (y + 38) ← multiply both sides by 2 to clear the fraction

2y - 18 = y + 38 ( subtract y from both sides )

y - 18 = 38 ( add 18 to both sides )

y = 56

8 0
2 years ago
Use common denominators to determine whether the ratios form a proportion.
AURORKA [14]
They are not in proportion, since its 6:9 round it down (2:3) so pretend the 6 are apples and the 9 are oranges

Every 2 apples there are 3 oranges

So having 9 apples what is that?

2 x ? = 9

2 x 4.5 = 9

So if you want to keep 2:3 you have you times the oranges by 4.5 aswell!

3 x 4.5 = 13.5

So since it is 9:12 not 9:13.5 they are not in proportion
7 0
3 years ago
Read 2 more answers
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