Answer:
It defines five ICMPv6 packet types for router solicitation,router advertisement,neighbor solicitation,neighbor advertisement,and network redirects.
Explanation:
Answer:
Network mapping.
Explanation:
Network mapping seems to be the method of mapping the server visibly and rationally in order to determine the relations at mid of the network as well as the not same nodes.
- Network mapping is the practice of security checking using software to search against services running on networks.
- Network performance applications and software contains certain network mapping functions that customize the network
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
I am progressing on learning Python, gonna get back to you and complete what you ask as a practice.
Answer
Is that really a question?
Explanation:
Ok I will
