Determine the value of x.
1 answer:
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Answer:
Given: A parallelogram EFGH in which diagonals intersect at point J.
To Find: A segment congruent to EJ.
Solution: In parallelogram EFGH
Point of intersection of Diagonals EG and FH are point J.
As we know diagonals of parallelogram bisect each other.
So, EJ=JG and FJ=JH
∵ Solution is EJ≅ JG
6x^4-17x^3-7x^2+13x=3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3
6x^4-17x^3-7x^2+13x-3=3-3
6x^4-17x^3-7x^2+13x-3=0
y=6x^4-17x^3-7x^2+13x-3
y=0
The solutions are: x=-1, 1/2, 1/3 and 3