Question

If an object is dropped from the height of 54 feet,

Answer 1

Answer:

b

Step-by-step explanation:

When the object hits the ground , the h = 0 , that is

- 16t² + 54 = 0 ( subtract 54 from both sides )

- 16t² = - 54 ( divide both sides by - 16 )

t² = $\frac{54}{16}$ ( take square root of both sides )

t = $\sqrt{\frac{54}{16} }$ ≈ 1.84 seconds ( to 2 dec. places )