what is the equation in point slope form of the line passing through (-2,-5) and (2,3)
Point slope form: y - y1 = m(x - x1)
m = (3 + 5)/(2 + 2) = 8/4 = 2
Point slope form:
y - 3 = 2(x - 2) if you're using this (2,3)
or
y + 5 = 2(x + 2) if you're using this (-2,-5)
<span>A flat surface of a solid figure is called a "face".
Your answer is <em>face.
</em>
</span>
Answer:
x = 71°
Step-by-step explanation:
The angles of any triangle will always amount to 180°.
Which means: (Angle of A) + (Angle of B) + (Angle of C) = 180°
Placing the known values into that equation will always let you know the third angle of any triangle.
(Angle of A) + (Angle of B) + (Angle of C) = 180°
(38°) + (71°) + (x) = 180°
109° + x = 180°
Solve for x by subtracting 109° from both sides
x = 180° - 109°
x = 71°
OR you can add the other two known angles 38° + 71° = 109°
This subtracted from the 180°
180° - 109° = 71°
Answer:
time = 1secs
<em>Max height = 25metres</em>
Step-by-step explanation:
Let the equation that models the height of the ball be expressed as;
h(t) = −16t^2 + 32t + 9
t is the time in seconds
The velocity of the ball at its maximum height is zero i.e dh/dt = 0
dh/dt = -32t + 32
0 = -32t + 32
32t = 32
t = 32/32
t = 1 seconds
The ball will reach its maximum height after 1 seconds.
Get the maximum height reached. Substitute t = 1 into the modeled function;
h(t) = −16t^2 + 32t + 9
h(1) = −16(1)^2 + 32(1) + 9
h(1) = −16 + 32 + 9
h(1)= 16+9
<em>h(1) = 25</em>
<em>Hence the maximum height reached is 25metres</em>
