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3 years ago

7

Find the 13th term of the geometric sequence 5, 10, 20, ...

1 answer:

const2013 [10]3 years ago

6 0

5,10,20,40,80,160,320,640,1280,2560,5120,10240,20480

= 20480

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[ correction added, Thanks to @stef68 ]

$\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)$

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4 years ago