Answer:
"Router screening" is the correct option.
Explanation:
- A router that philters packets like a firewall. For certain instances, the whole firewall system is such a single scanning router.
- Often connected to a network stage as well as a container-filter firewall has been the scanning router firewall. This rather firewall operates by filtering protocol characteristics from received packets.
So that the above seems to be the correct approach.
Answer: The best method to avoid getting spyware on a user machine is to download software only from trusted websites. And depending on the machine it might say that "This download you are about to install might have spyware or malware and it might infect your laptop" "Do you wish to continue?"
Answer:
U.S. Bureau of Labor Statistics.
Explanation:
The Bureau of Labor Statistics is a unit of the United States Department of Labor assigned with the task of fact-finding in the field of labor and statistics for the government. The agency helps measure the labor activity in the market and evaluates all forms of activity regarding labor conditions for the government.
This agency also functions or serves as the principal agency for the United States Federal Statistical System. It not only collects information or data but also helps spread the said information to the government. It also published a biennial handbook describing various occupations.
The designer could use the measurements in pixels.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
