The problem would be 12 divided by 4 + 6 x 8 + 2.
This is because 12/4 = 3, and since PEMDAS says multiplication and division before addition and subtraction you would do 6 x 8 = 48. 3 + 48 = 51. 51 + 2 = 53. I was glad to help! :D
Answer:
99% confidence interval for the population average examination score is between a lower limit of 69.2872 and an upper limit of 82.7128.
Step-by-step explanation:
Confidence interval = mean +/- margin of error (E)
mean = 76
variance = 144
sd = sqrt(variance) = sqrt(144) = 12
n = 25
degree of freedom (df) = n - 1 = 25 - 1 = 24
confidence level (C) = 99% = 0.99
significance level = 1 - C = 1 - 0.99 = 0.01 = 1%
t-value corresponding to 24 df and 1% significance level is 2.797
E = t×sd/√n = 2.797×12/√25 = 6.7128
Lower limit = mean - E = 76 - 6.7128 = 69.2872
Upper limit = mean + E = 76 + 6.7128 = 82.7128
99% confidence interval is (69.2872, 82.7128)
Answer:
ok ask the question plzzzzz
Answer:
a,e,c,b,d
Step-by-step explanation:
i think that is it but im not completly sure
