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dlinn [17]
2 years ago
9

Simplify the expression.

Mathematics
2 answers:
marysya [2.9K]2 years ago
6 0

Answer:

12x - 6

Step-by-step explanation:

4 + 15x - 10 -3x

(15x - 3x) + (4-10)

12x - 6

Amiraneli [1.4K]2 years ago
4 0
Im a Filipino disguised as an American citizen
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87,521 rounded to the nearest hundred
givi [52]

Answer:

87,500

Step-by-step explanation:

Since the last 2 digits arent 5 or greater than 5 it can not be rounded to the next hundred.

3 0
3 years ago
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Help please need help please
lapo4ka [179]

Answer:

The 1st y with the 4th card

The 2nd y with the 3rg card

The 3th y with the 2nd card

The 4th y with the 1st card

7 0
3 years ago
A regular hexagon is dilated by a scale factor of 7/5 to create a new hexagon. How does the perimeter of the new hexagon compare
Airida [17]
<span>It's the same ratio, 7/5.</span>
3 0
4 years ago
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A savings account earns 15% interest annually. What is the balance after 8 years in the savings account when the initial deposit
natita [175]

The balance after 8 years is $22,942.67

<h3>What is the balance after 8 years?</h3>

We know that the savings account earns 15% annually, and the initial deposit is $7500, then the balance as a function of time in years is:

B = $7500*(1 + 15%/100%)^t

B = $7500*(1.15)^t

The balance after 8 years is what we get when we evaluate the above function in t = 8, so we get:

B = $7500*(1.15)^8 = $22,942.67

So the correct option is the last one.

If you want to learn more about exponentials:

brainly.com/question/2456547

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3 0
2 years ago
Prove that if the set of vectors {u1, u2, u3} is linearly dependent and u4 is any vector, then the set {u1, u2, u3, u4} is linea
Lesechka [4]

Answer with Step-by-step explanation:

We are given that the set of vectors{u_1,u_2,u_3} is lineraly dependent set .

We have to prove that the set {u_1,u_2,u_3,u_4} is linearly dependent .

Linearly dependent vectors : If the vectors u_1,u_2.u_3,u_4

are linearly  dependent therefore the linear combination

a_1u_1+a_2u_2+a_3u_3+a_4u_4=0

Then ,there exit a scalar which is not equal to zero .

Let a_1\neq0 then the vector u_1 will be zero and remaining  other vectors are not zero.

Proof:

When u_1,u_2,u_3 are linearly dependent vectors therefore, linear combination of vectors of given set

a_1u_1+a_2u_2+a_3u_3=0

By definition of linearly dependent vector

There exist a scalar which is not equal to zero.

Suppose a_1\neq 0 then  u_1=0

The linear combination of the set {u_1,u_2,u_3,u_4}

a_1u_1+a_2u_2+a_3u_3+a_4u_4=0

When a_1\neq0\; and\; u_1=0

Therefore,the set {u_1,u_2,u_3,u_4} is linearly dependent because it contain a vector which is zero.

Hence, proved .

5 0
3 years ago
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