The amortization formua I'm familiar with assumes payments are made at the end of the period, so we'll use it for the part after the first payment has already been made.
.. A = 4,000
.. P = 500,000 -4000 = 496,000
.. i = 0.06
.. n = 12
.. t = to be determined
And the formula is
.. A = Pi/(n(1 -(1 +i/n)^(-nt))) . . . . . amortization formula with payments at the end of the period
.. 1 -(1 +i/n)^(-nt) = Pi/(An) . . . . . . rearrange to get "t" factor in numerator
.. 1 -Pi/(An) = (1 +i/n)^(-nt) . . . . . . get "t" factor by itself
.. log(1 -Pi/(An)) = -nt*log(1 +i/n) . . . . use logarithms to make the exponential equation into a linear equation
.. log(1 -Pi/(An))/(-n*log(1 +i/n)) = t . . . . divide by the coefficient of t
.. t = 16.1667 . . . . . years (after the first monthly withdrawal)
The plan will support withdrawals for 16 years and 3 months (195 payments).
Answer:
-0.125
Step-by-step explanation:
C. 2x+5
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Answer:
The opposite of -11 is 11, and I dont understand what else you're asking
Step-by-step explanation:
