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Firlakuza [10]
2 years ago
5

The weight of an object on moon is 1/6 of its weight on Earth. If weight of an object on Earth is 18/5 kg, what would be its wei

ght on moon? ​Please help me!!!!​
Mathematics
2 answers:
DiKsa [7]2 years ago
8 0

Answer:

Solution given:

weight of moon=1/6 th of Earth

If weight of Earth is 18/5 kg

weight of moon=?

we have

<u>weight of </u>moon: 1/6 of weight of Earth

=1/6*18/5

=3/5kg

<u>I</u><u>t</u><u>s</u><u> </u><u>w</u><u>e</u><u>i</u><u>g</u><u>h</u><u>t</u><u> </u><u>o</u><u>n</u><u> </u><u>m</u><u>o</u><u>o</u><u>n</u><u> </u><u>i</u><u>s</u><u> </u><u>3</u><u>/</u><u>5</u><u> </u><u>k</u><u>g</u>

IrinaVladis [17]2 years ago
4 0

Answer:

  • 3/5 kg

Step-by-step explanation:

The weight of an object on Moon is 6 times smaller than same on Earth.

<u>If it weights 18/5 kg on Earth then its weight  on Moon is:</u>

  • 18/5 * 1/6 = 3/5 kg
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Soleil and Malvin each work a job. Soleil starts with $700 and makes $100 per day. Malvin starts out with $200 and makes $120 pe
Goshia [24]

Answer:

Soleil and Malvin would have $ 5,000 all together after 13 days.

Step-by-step explanation:

Since Soleil and Malvin each work a job, and Soleil starts with $ 700 and makes $ 100 per day while Malvin starts out with $ 200 and makes $ 120 per day, to determine after how many days will they have at least $ 5000 all together it must be done the following calculation:

5,000 - 700 - 200 = 4,100

200X + 120X = 4,100

320X = 4,100

X = 4,100 / 320

X = 12.8

So Soleil and Malvin would have $ 5,000 all together after 13 days.

5 0
3 years ago
There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

4 0
2 years ago
Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me
Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

V= \pi r^2 h

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr

So finding the partial derivatives we get

dV =\pi r^2 dh + \pi 2r h dr

dV =\pi r^2 dh + 2\pi r h dr

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)

That give us

V= 28 \pi  \, cm^3

Or in decimal value

\boxed{dV= 87.96 \, cm^3}

Thus the volume of metal in the can is 87.96 cubic cm.

6 0
3 years ago
Simplify square root<br>​
Tasya [4]

Answer:

Here is the rule: when a and b are not negative

√(ab) = √a × √b

Example: simplify √8

√8 = √(4×2) = √4 × √2 = 2√2

(Because the square root of 4 is 2)

In other words 2 x 4 = 8 = √2 x 4 but 4 can be simplified more (2 x 2) so 2 (previous 4) moves to the left of the square root leaving  2√2

To simplify a square root: make the number inside the square root as small as possible (but still a whole number)

or you can use a simplifying square root calculator.

8 0
3 years ago
A loaf of bread is cut into slices of equal size. Some of the loaf is used in a recipe and 2/12 of the loaf is used to make a sa
gtnhenbr [62]
Answer:
Fraction of bread used in the recipe is 3/12 which can be further simplified into 1/4

Explanation:
The original loaf of bread is 100% complete (no fraction is taken from it yet). This means that the value of the original loaf is 12/12

Now, assume that the fraction used in the recipe is x

We know that:
2/12 of the loaf was used in making a sandwich
7/12 of the oaf was put in the refrigerator

Therefore:
complete loaf = fraction used in making a sandwich + fraction used in making recipe + fraction put in refrigerator
12/12 = x + 2/12 + 7/12
12/12 = x + 9/12
x = 12/12 - 9/12
x = 3/12 

Hope this helps :)
5 0
3 years ago
Read 2 more answers
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