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2 years ago

Enter the expression using exponents.

Mathematics

2 answers:

Mamont248 [21]2 years ago

7 0

Answer/Step-by-step explanation:

You see that there is 3, 2s there. Meaning you add them up and use the amount there is as your exponent.

so your answer is $2^{3}$

mario62 [17]2 years ago

7 0

Is it 2 the power of 3

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Use the figure to identify each pair of angles as complementary angles, supplementary angles, vertical angles, or none of these.

zhenek [66]

Answer:

a is true and becomes complimentary as they both add up to 90 degree.

b. is true it is the only vertical angle group. As points AE, and BD cross and create these angles.

c is supplementary as both 3,4 together add up to 180

but each of these do not fit other description, as 5,1 would be also supplementary if 2 was in that group.

Step-by-step explanation:

Points 3, 4 as a group and 3,2,1 as a group and 2,1,5 as a group are each supplementary as each group add up to 180 degree. 1,5 on its own is not supplementary

Points 2 is complimentary on its own and also 1,5 combined are complimentary so this is true and 1,5 on its own as a group is complimentary.

Points 3,5 become vertical angles as a group.

Angles A:B + D:E are also vertical angles this shows points 1,2 and 4 as a group of vertical angles.

Vertical Angles are the angles opposite each other when two lines cross. "Vertical" in this case means they share the same Vertex (corner point), not the usual meaning of up-down

8 0

3 years ago

HELP ASAP WILL MARK BRAINLIEST

zhenek [66]

Answer:

Step-by-step explanation:

I did it and got it right hope you do too : )

7 0

3 years ago

The probability of rolling a number less than 3 on a number cube 2/6. Jennifer rolls a number cube 60 times how many times shoul

Savatey [412]

Answer:

20 times

Step-by-step explanation:

Given the following :

Probability of rolling a number less than 3 on a number cube:

Required outcome = (1, 2)

Total possible outcomes = (1, 2, 3, 4, 5, 6)

Required outcome / Total possible outcomes

= 2 /6

= 1/3

Hence, if number cube is rolled 60 times, number of times a number less than 3 is expected :

(Probability of obtaining a number less than 3 in one roll × number of rolls)

= (1 / 3) × 60

= 60 / 3

= 20 times

5 0

3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

6 0

3 years ago

Last year Golden State Warriors won 80% of the first 15 matches. Then they won the rest of the three matches. What percent of al

MrMuchimi

Answer:

83.33%

Step-by-step explanation:

We first need to evaluate 80% of the first 15 matches in order to determine the number of watches out of 15 which they won.

80 % of 15 = 80/100 * 15 = 12

12 matches out of the first 15 were won.

Since the team won the rest of the 3 remaining matches, the total number of matches won becomes;

12 + 3 = 15

The team thus won 15 matches out of a total of 15 + 3 =18 matches .

The percent of all matches won is ;

15/18 * 100 = 83.33%

3 0

3 years ago