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2 years ago

Enter the expression using exponents.

Mathematics

2 answers:

Mamont248 [21]2 years ago

7 0

Answer/Step-by-step explanation:

You see that there is 3, 2s there. Meaning you add them up and use the amount there is as your exponent.

so your answer is $2^{3}$

mario62 [17]2 years ago

7 0

Is it 2 the power of 3

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3 years ago

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2 years ago

Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0

lorasvet [3.4K]

Answer:

equation;

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

Center (-4,2)

Radius is

$3 \sqrt{3}$

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

$(x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

Where (h,k) is center

r is the radius

So first we group like Terms together

${x}^{2} + 8x + {y}^{2} - 4y - 7 = 0$

Add 7 to both sides

${x}^{2} + 8x + {y}^{2} - 4y = 7$

$( {x}^{2} + 8x) +( {y}^{2} - 4y) = 7$

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

$(\frac{8}{2} ) {}^{2} = 16$

and

$( - \frac{4}{2} ) {}^{2} = 4$

so we have

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 7 + 16 + 4$

${x}^{2} + 8x + 16 + {y}^{2} - 4y + 4y = 27$

$(x + 4) {}^{2} + (y - 2) {}^{2} = 27$

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

$\sqrt{27} = 3 \sqrt{3}$

So the radius is 3 times sqr root of 3.

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2 years ago

Solve for x. Express the answer in simplest form. <br><br> 2/1 = 8z -2/9

aleksandr82 [10.1K]

5/18 or in dec .27777777

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3 years ago

X+7=5x2 what's the answer

Helen [10]

Answer: 3

Explanation:

x + 7 = 5 x 2

you do 5(2) and get 10

plug in 10 and the equation looks like:

x + 7 = 10

from there you would subtract 7 from 7 and 10 to isolate x and get your answer of:

x = 3 :)

3 0

3 years ago