Answer:
1. SORRY IDK
2. B.
3. D
4. C
Step-by-step explanation:
<h3>
Answer: 127</h3>
=================================================
Explanation:
The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.
The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.
Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.
So we have these scores
- first exam = 70
- second exam = 80
- third exam = 43
- fourth exam = x+5
Adding up these scores and dividing by 4 will get us the average
(sum of scores)/(number of scores) = average
(70+80+43+x+5)/4 = 80
(x+198)/4 = 80
x+198 = 4*80
x+198 = 320
x = 320 - 198
x = 122
So the student got a score of x+5 = 122+5 = 127 on the fourth exam.
Answer: x=9
you can reduce multiply to show your work
3• 1/3x = 3•3
9=9
I THINK THE ANSWER WOULD BE 2A\a+b=h
Answer:
Step-by-step explanation:
y = e^(-3x)
Stretch by factor of 4
y = 4e^(-3x)
Reflect across y axis
y = 4e^(3x)
Shift up by 5
y = 4e^(3x) + 5
