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atroni [7]
3 years ago
7

Ada, Betty, Chris, and David have $45 in total. If Ada gets $2 from Betty, Chris triples his money, and David's money is cut by

half, four of them have the same amount. Initially, Ada has??
Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0

Answer:

7

Step-by-step explanation:

masya89 [10]3 years ago
4 0

The amount of money Ada have initially is $9.25 and this can be determined by forming the linear equation.

Given :

  • Ada, Betty, Chris, and David have $45 in total.
  • If Ada gets $2 from Betty, Chris triples his money, and David's money is cut by half, four of them have the same amount.

The following steps can be used in order to determine the money Ada have initially:

Step 1 - Let the total money of Ada be 'a', Betty be 'b', Chris be 'c', and David be 'd'.

Step 2 - The linear equation that represents the total money they have is given by:

a + b + c + d + = 45   --  (1)

Step 3 - Now, after Ada gets $2 from Betty, Chris triples his money, and David's money is cut by half, four of them have the same amount of money.

Step 4 - Let the amount of money they all have be 'x' then:

4x = 45         ----         (from equation (1))

x = $11.25

Step 5 - The initial amount of money Ada have is:

x = a + 2

11.25 = a + 2

11.25 - 2 = a

a = $9.25

So, Ada have $9.25 initially.

For more information, refer to the link given below:

brainly.com/question/2263981

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