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3 years ago

What’s the x value of the equation 30= 5x

Mathematics

1 answer:

Crank3 years ago

7 0

Answer:

x=6

Step-by-step explanation:

you dived the 5 to get x by itself and 5 dived by 30 is 6

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AB = 6x DC = x + 15 AD = 9 BC = 3y Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent. Show tha

Kruka [31]

Answer:

The given quadrilateral is a parallelogram.

Step-by-step explanation:

If a quadrilateral is a parallelogram , then the opposite sides would be equal.

Here we are going to equate the length of 1 pair of opposite sides to find the value of x and use this value of x to verify whether the other pair of opposite sides are equal.

AB = 6x

BC = 3x

DC = x + 15

AD = 9

Equate AB and CD,

6x = x + 15

5x = 15

x = 3

Now BC and DA should be equal.

BC = 3x = 9

Also DA = 9

As we can see, the other pair of opposite sides are also equal.

Quadrilateral ABCD is a parallelogram if both pairs of opposite sides are congruent.

Hence , the given quadrilateral is a parallelogram.

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3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago