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lyudmila [28]
2 years ago
6

Points A, B and C lie on a circle, centre O. Angle AOC = 142°. Find the value of y.

Mathematics
1 answer:
aksik [14]2 years ago
5 0

The value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

Let suppose that quadrilateral OABC is a parallelogram. Then, the following conditions must be fulfilled:

  1. \overline {OA} \cong \overline {BC}
  2. \overline{AB} \cong \overline{OC}
  3. \angle AOC \cong \angle ABC

In addition, if we have a rhombus we have the additional condition as A, B and C lie on the circle:

\overline{OA} \cong \overline {AB} \cong \overline {BC} \cong \overline{OC} (4)

If we know that \angle AOC = 142^{\circ}, then the value of \angle ABC = y = 142^{\circ}.

Based on all these finding, we conclude that the value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

To learn more on parallelograms, we kindly invite to check this verified question: brainly.com/question/555469

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Step-by-step explanation:

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<em>☽------------❀-------------☾</em>

<em>Hi there!</em>

<em>~</em>

<em>The absolute value is the distance from 0 to 2.5. In this case the absolute value from 0 to |2.5| is 2.5 </em>

<em>❀Hope this helped you!❀</em>

<em>☽------------❀-------------☾</em>

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