Given:
The x and y axis are tangent to a circle with radius 3 units.
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:
Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting 
, we get
Therefore, the standard form of the given circle is .
Answer:
The answer is D. -3, 6, 11
Step-by-step explanation:
A coefficient is a number used to multiply a variable.
Example: 6z means 6 times z, and "z" is a variable, so 6 is a coefficient. Variables with no number have a coefficient of 1.
Example: x is really 1x.
A number that cannot be expressed that way is irrational. For example, one third in decimal form is 0.33333333333333 (the threes go on forever). However, one third can be express as 1 divided by 3, and since 1 and 3 are both integers, one third is a rational number.
hope it helps!
Answer:
A, B, C all have one solution.
Step-by-step explanation:
1) Each equation in this question has one variable (x). This means that only one solution will be there.
2) Solve for x, you can cross out option D. When you subtract 52x from both sides, you're left with 52 = -78
Which is not true
3) Option A, if solved x = -65/68
4) Option B, x = 13/2
5) Option C, x = 5
All except D, have one solution, I don't know if it's a multiple choice answer but this is how I can help.
Answer:
C & D
Step-by-step explanation:
x² + 3x - 3 = 0
a = co efficient of x² = 1
b= co efficient of x = 3
c = constant = -3
roots = (-b ± 
)/2a
= (-3±![\sqrt{3^{2}-4*1*[-3]}](https://tex.z-dn.net/?f=%5Csqrt%7B3%5E%7B2%7D-4%2A1%2A%5B-3%5D%7D)
)/2*1
= (-3±
)/2
= (-3±√21)/2
