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Ksju [112]
2 years ago
13

Josh Collins plans to buy a house for $245,000. If that real estate is expected to increase in value by 7 percent each year, wha

t will its
approximate value be six years from now? Use Exhibit 1-A. (Round time value factor to 3 decimal places and final answer to the

nearest whole number.)

Approximate value
Mathematics
1 answer:
Oksana_A [137]2 years ago
5 0

Using an exponential function, it is found that it's approximate value six years from now will be of $367,679.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^t

In which:

  • A(0) is the initial value.
  • r is the growth rate, as a decimal.

In this problem:

  • Josh Collins plans to buy a house for $245,000, hence A(0) = 245000.
  • That real estate is expected to increase in value by 7 percent each year, hence r = 0.07

Then:

A(t) = A(0)(1 + r)^t

A(t) = 245000(1 + 0.07)^t

A(t) = 245000(1.07)^t

In six years, we have that t = 6, hence, the value will be of:

A(6) = 245000(1.07)^6 = 367679

You can learn more about exponential functions at brainly.com/question/25537936

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Step-by-step explanation:

Step 1:

In the triangle, the angle is 40°, the opposite side has a length of 26 units, the adjacent side has a length of x units while the hypotenuse is not given.

To determine the value of x, we determine the value of the tan of the given triangle.

To calculate the tan of angle A we divide the opposite side's length by the the adjacent side's length.

tan A = \frac{oppositeside}{adjacent side}.

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The length of the opposite side = 26 units.

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If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f
nikklg [1K]

The quadratic function given by:


f(x)=a(x-h)^2+k, \ \ \ a\neq 0


is in vertex form. The graph of f is a parabola whose axis is the vertical line x=h and whose vertex is the point (h, k). So:


To translate the graph of a function to the right, left, upward or downward we have:

For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)


By knowing this things, we can solve our problem as follows:


FIRST.

  • Translating <em>11 units to the left:</em>

g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2


  • Then translating<em> 5 units down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5


Since the new function is fatter, the factor we need to multiply the term (x+11)^2 <em>must be</em> less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.


<em>Therefore, the right answer is </em><em>b. f(x) = 1/2(x + 11)^2 - 5</em>


SECOND.

  • Translating <em>8 units to the right:</em>

g(x)=f(x-8) \\ \\ \therefore g(x)=(x-8)^2


  • Then translating<em> 1 unit down:</em>

g(x)=f(x)-c \\ \\ \therefore g(x)=(x-8)^2-1


As explained in the previous case, there are two factors 1/3 and 3, so we choose the first one.


<em>Therefore, the right answer is </em><em>a. g(x) = 1/3(x - 8)^2 - 1</em>

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