The fence is 210 ft long.
There is a post every 3.5 ft.
If you divide 210 ft by 3.5 ft, you get the number of spaces between posts.
(210 ft)/(3.5 ft) = 60
The fence starts with a post. Then there is 3.5 ft of fencing. Then there is another post. Then there is another 3.5 ft of fencing followed by a post. In total there are 61 posts.
Here's another way of thinking of why you end up with 60 posts.
For each 3.5 ft of fencing, you place a post at the end of the fencing.
Since there are 60 3.5-ft-long pieces of fencing, there will be 60 posts, one at the end of each piece of fencing. The first thing that is done is to put the initial post before any fencing is put up. The first post plus 60 more posts add up to 61 posts.
Now that you see why there are 61 posts, we can calculate their cost.
61 * $8.50 = $518.50
Answer:
A = 57.97 cm²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 6.2, a = 10.8 and b = 7.9, thus
A = × 6.2 × (10.8 + 7.9) = 3.1 × 18.7 = 57.97 cm²
Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied
7720(1+0.01)^n = 3200(1+0.0375)^n
or
7720x1.01^n = 3200x1.0375^n
Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n
Answer: P = 0.75
Step-by-step explanation:
Hi!
The sample space of this problems is the set of all the possible sales. It is divided in the disjoint sets:
We have also the set of sales of boat accesories 
, the colored one in the image.
We are given the data:
From these relations you can compute the probabilities of the intersections colored in the image:
You are asked about the conditional probability:
To calculate this, you need 
. In the image you can see that the set is the union of the two disjoint pink and blue sets. Then:
Finally:
