9514 1404 393
Answer:
g = 12
Step-by-step explanation:
You recognize that 144 is 12², so you check to see if the x-coefficient is 2·12. It is. The quadratic is a square:
(g -12)² = 0
The only solution is the one that makes the squared term equal to zero:
g -12 = 0
g = 12
_____
The square of a binomial is ...
(a +b)² = a² +2ab +b²
Here, we have a=x, b=-12.
Dish A has n₁ = 1.75 x 10¹⁸ bacteria.
Dish B has n₂ = 6.25 x 10¹⁵ bacteria.
Calculate n₁/n₂.
![\frac{n_{1}}{n_{2}} = \frac{1.75 \times 10^{18}}{6.25 \times 10^{15}} =0.28 \times 10^{18-15} = 0.28 \times 10^{3} =2.8 \times 10^{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bn_%7B1%7D%7D%7Bn_%7B2%7D%7D%20%3D%20%5Cfrac%7B1.75%20%5Ctimes%2010%5E%7B18%7D%7D%7B6.25%20%5Ctimes%2010%5E%7B15%7D%7D%20%3D0.28%20%5Ctimes%2010%5E%7B18-15%7D%20%3D%200.28%20%5Ctimes%2010%5E%7B3%7D%20%3D2.8%20%5Ctimes%2010%5E%7B2%7D)
The number of times that the number of bacteria in dish A is greater than the number of bacteria in dish B is 2.8 x 10² in standard notation.
Answer: 2.8 x 10²
Answer:
12
Step-by-step explanation:
Answer:
The triangle with side lengths 7 in, 11 in, 13 in will be an acute angled triangle.
Step-by-step explanation:
If we assume that the triangle with height 7 inches and base 11 inches of a right triangle then its hypotenuse will have the length of
inches.
But the third side of the triangle is given to be 13 inches which is less than 13.04 inches i.e. 13 < 13.04.
Therefore, the triangle with side lengths 7 in, 11 in, 13 in will be an acute-angled triangle. (Answer)
A point of concurrency is a place where three or more, but at least three lines, rays, segments or planes intersect in one spot. If they do, then those lines are considered concurrent, or the the rays are considered concurrent. Hope it helps!